2x^2-8x+9=-8x+137

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Solution for 2x^2-8x+9=-8x+137 equation:



2x^2-8x+9=-8x+137
We move all terms to the left:
2x^2-8x+9-(-8x+137)=0
We get rid of parentheses
2x^2-8x+8x-137+9=0
We add all the numbers together, and all the variables
2x^2-128=0
a = 2; b = 0; c = -128;
Δ = b2-4ac
Δ = 02-4·2·(-128)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*2}=\frac{-32}{4} =-8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*2}=\frac{32}{4} =8 $

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